题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main() {
int b;
scanf("%d",&b);
int i;
int sum =1;
for(i=1;i<=b;i++)
{
sum*=2;
}
printf("%d",sum);
return 0;
}
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