题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
s_in = input()#输入字符串，赋值为s_in
a = {}
for i in s_in:#遍历字符串，以字符串的字符为键，出现次数为值
if i in a:
a[i] += 1
else:
a[i] = 1
m = min(a.values())#在字典中，找出数值最小的值m
ma = []
for k, v in a.items():#遍历字典，找出出现次数最小的值的键，并添加到列表ma中
if v == m:
ma.append(k)
for i in s_in:#遍历输入字符串，如果当前字符串是找出的出现次数最低的字符，则不输出，否则正常输出
if i in ma:
continue
else:
print(i, end = '')
#华为机试#
