题解 | #删除链表的节点#
删除链表的节点
https://www.nowcoder.com/practice/f9f78ca89ad643c99701a7142bd59f5d
struct ListNode* deleteNode(struct ListNode* head, int val ) {
// write code here
if(head->val==val) return head->next;
else{
struct ListNode* s=head;
while(head->next!=NULL){
if(head->next->val==val){
head->next=head->next->next;
}
else{
head=head->next;
}
}
return s;
}
}

