题解 | #JZ24 反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/*
struct ListNode {
int val;
struct ListNode *next;
ListNode(int x) :
val(x), next(NULL) {
}
};*/
class Solution {
public:
ListNode* ListInsert(ListNode* head, int x){
ListNode* newnode = new ListNode(x);
if(head == NULL){
head = newnode;
}
else{
newnode -> next = head;
head = newnode;
}
return head;
}
ListNode* ReverseList(ListNode* pHead) {
ListNode* result = NULL;
if(pHead != NULL){
while(pHead -> next !=NULL){
result = ListInsert(result, pHead -> val);
pHead = pHead -> next;
}
result = ListInsert(result, pHead -> val);
}
return result;
}
};
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