题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
allnumber = int(input())
numberlist = input().split(' ')
k = int(input())
if k!=0:
print(numberlist[-k])
else:
print('')
except:
break注意倒数从1开始，而不是0开始，所以要把0去掉
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