题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
str1 = input()
list1 = []
list2 = []
list3 = []
str2 = ''
for i in str1:
list1.append(i)
n = str1.count(i)
list2.append(n)
num = min(list2)
for j in range(len(list2)):
if list2[j] == num:
list3.append(j)
for k in list3:
list1[k] = ''
for j in list1:
str2 = str2+j
print(''.join(str2))
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hhhhhhhz：感觉还是很优秀了，可能嵌入式的岗位太少了吧，身边大部分嵌入式的朋友都有这种焦虑