题解 | #占空比50%的奇数分频#
占空比50%的奇数分频
https://www.nowcoder.com/practice/ccfba5e5785f4b3f9d7ac19ab13d6b31
解法1:上下边沿取或
`timescale 1ns/1ns module odo_div_or ( input wire rst , input wire clk_in, output wire clk_out7 ); //*************code***********// reg clk_neg, clk_pos; reg [2:0] cnt; always@(posedge clk_in or negedge rst) begin if(~rst) cnt <= 0; else cnt <= cnt==6? 0: cnt+1; end always@(posedge clk_in or negedge rst) begin if(~rst) clk_pos <= 0; else clk_pos <= cnt==3||cnt==6? ~clk_pos: clk_pos; end always@(negedge clk_in or negedge rst) begin if(~rst) clk_neg <= 0; else clk_neg <= cnt==3||cnt==6? ~clk_neg: clk_neg; end assign clk_out7 = clk_neg|clk_pos; //*************code***********// endmodule