题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
double Power(double base, int exponent) {
double res=1;
for(int i=0;i<(exponent>0?exponent:-exponent);i++)
res*=base;
if(exponent>0)
return res;
else
return 1/res;
}
