题解 | #统计活跃间隔对用户分级结果#

SELECT
	M.us user_grade,
	round( count( M.us ) / ( SELECT count( DISTINCT uid ) FROM tb_user_log ), 2 ) ratio
FROM
	(
	SELECT
		(
		CASE
				
				WHEN timestampdiff( DAY, N.mada, N.md ) >= 7 
				AND timestampdiff( DAY, N.mida, N.md ) < 30 THEN
					"沉睡用户" 
					WHEN timestampdiff( DAY, N.mida, N.md ) < 7 THEN "新晋用户" WHEN timestampdiff( DAY, N.mada, N.md ) >= 30 THEN
					"流失用户" 
					WHEN timestampdiff( DAY, N.mada, N.md ) < 7 THEN
					"忠实用户" 
				END 
				) us 
			FROM
				(
				SELECT
					( SELECT date_format( max( in_time ), "%Y-%m-%d" ) FROM tb_user_log ) md,
					date_format( min( tul.in_time ), "%Y-%m-%d" ) mida,
					date_format( max( tul.in_time ), "%Y-%***da,
					tul.uid 
				FROM
					tb_user_log tul 
				GROUP BY
					tul.uid 
				) N 
			) M 
		GROUP BY
			M.us
        order by ratio desc