题解 | #求int型正整数在内存中存储时1的个数#

number = int(input()) dig = bin(number) list1 = list(dig) list1.reverse() str1 = ''.join(list1) count = 0 for i in str1: if i == '1' or i == '0': if i == '1': count = count + 1 else: break print(count)