题解 | #牛牛学数列3#
牛牛学数列3
http://www.nowcoder.com/practice/f65c726d081c4160a9356eabf0dc21d9
#2022/5/23 21:06
#1 1
#2 1+1/-2
#3 1+1/-2+1/3+1/-4
n=int(input())
sum1,sum2=0,0
for i in range(1,n+1):
if i%2==0:
sum1+=-(1/i)
else:
sum2+=1/i
print("{:.3f}".format(sum1+sum2))
#1 1
#2 1+1/-2
#3 1+1/-2+1/3+1/-4
n=int(input())
sum1,sum2=0,0
for i in range(1,n+1):
if i%2==0:
sum1+=-(1/i)
else:
sum2+=1/i
print("{:.3f}".format(sum1+sum2))
