9.14 荣耀笔试幸运抽奖
JS实现的,帮同学做的,原题没看完整,不知道对不对。
let xx = 'Nick', xxn = 0; // 嘉宾名和嘉宾的幸运值
let list = ['Tom', 'Jerry', 'Spike', 'Bob', 'Frank'];
let obj = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5, 'f': 6, 'g': 7, 'h': 8, 'i': 9, 'j': 10, 'k': 11, 'l': 12, 'm': 13,
'n': 14, 'o': 15, 'p': 16, 'q': 17, 'r': 18, 's': 19, 't': 20, 'u': 21, 'v': 22, 'w': 23, 'x': 24, 'y': 25, 'z': 26}
xx = xx.toLowerCase();
for (let i of xx) {
xxn = xxn + obj[i];
}
console.log('嘉宾的幸运值为:', xxn);
console.log('抽奖人员名字及幸运值为:', list);
let len = list.length;
let lacky = [], pai = [], who;
for (let i = 0; i < len; i++) {
let n = 0;
list[i] = list[i].toLowerCase();
for (let item of list[i]) {
n = n + obj[item];
}
lacky.push(n);
}
for (let j = 0; j < lacky.length; j++) {
let m = Math.abs(lacky[j] - xxn);
pai.push(m);
if (pai[j] < pai[j - 1]) {
who = list[j]
}
}
console.log(lacky)
console.log('跟嘉宾幸运值最接近的中奖者是', who, '!');
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