题解 | #合法IP#
合法IP
http://www.nowcoder.com/practice/995b8a548827494699dc38c3e2a54ee9
其实嘛，一个个去判断就可以了
对于不满足的条件直接打印退出就可以了
正常循环结束即是合法的IP
def ipp(ip):
a = ip.split('.')
if len(a) != 4 :
print('NO')
else:
for i in a :
if not i:
print('NO')
break
elif not i.isnumeric():
print('NO')
break
elif len(i) > 1 and i[0] == '0':
print('NO')
break
elif int(i) >= 255:
print('NO')
break
else:
print('YES')
ip = input().strip()
ipp(ip)
