题解 | #2的n次方计算#
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main(){
int n;
scanf("%d",&n);
printf("%d",1<<n);
return 0;
}
int main(){
int n;
scanf("%d",&n);
printf("%d",1<<n);
return 0;
}
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
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