题解 | #旋转字符串#
旋转字符串
http://www.nowcoder.com/practice/80b6bb8797644c83bc50ac761b72981c
#切片然后连接看连接后的字符串是不是和字符串B一样
class Solution:
def solve(self , A: str, B: str) -> bool:
# write code here
if len(A)!=len(B):
return False
if len(A)==len(B):
for i in range(len(A)):
if A[i:]+A[0:i]==B:
print(A[i:]+A[0:i])
return True
return False
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