题解 |CPP58 编写函数实现字符串翻转（引用方式）
编写函数实现字符串翻转（引用方式）
http://www.nowcoder.com/practice/46eb5bd3ebc544fc96d335c8cb7d30f1
#include #include using namespace std;
int main() {
int letter = 0;
int digit = 0;
int space = 0;
int other = 0;
char buf[1024] = {0};
cin.getline(buf, sizeof(buf));
for(int i=0;i<strlen(buf);i++){
if(buf[i]>='0'&&buf[i]<='9'){
digit++;
}else if((buf[i]>='A'&&buf[i]<='Z')||(buf[i]>='a'&&buf[i]<='z')){
letter++;
}else if(buf[i]==' '){
space++;
}else{
other++;
}
}
// write your code here......
cout << "letter:" << letter << " digit:" << digit << " space:" << space << " other:" << other << endl;
return 0;
}
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