题解 | #KiKi和酸奶#
KiKi和酸奶
http://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
int main()
{
int n,h,m;
scanf("%d %d %d",&n,&h,&m);
if (m <= n*h)
{
if (m%h == 0 || m == h)
{
n = n - m/h;
}
else
{
n = n -m/h - 1;
}
}
printf ("%d",n);
return 0;
}
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