题解 | #2的n次方计算#
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
int main()
{
int n =0;
scanf("%d",&n);
int a = 1;
a <<= n;
printf ("%d",a);
return 0;
}
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
int main()
{
int n =0;
scanf("%d",&n);
int a = 1;
a <<= n;
printf ("%d",a);
return 0;
}
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