题解 | #牛牛学数列2#
牛牛学数列2
http://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include<stdio.h>
int main()
{
int n=0;
scanf("%d",&n);
double sum=0.0;
int i=0;
for(i=1; i<n+1; i++)
{
sum+=1.0/i;
}
printf("%6f",sum);
return 0;
}