题解 | #牛牛学数列2#

#include<stdio.h>

int main()
{
    int i =1;
    double sum = 0.0;
    scanf("%d",&i);
    for(int j =1;j<=i;j++)
    {
        sum+=1.0/j;
    }
    printf("%.6lf\n",sum);
    return 0;
}