题解 | #鸡兔同笼#

只需注意奇数与偶数即可

#include<iostream>
using namespace std;
int main()
{
    int n;
    while(cin >> n){
        if(n % 2 != 0)
            cout << 0 << " " << 0 << endl;
        else{
            int minnum = (n / 4) + (n - n / 4 * 4) / 2;
            int maxnum = (n / 2);
            cout << minnum << " " << maxnum << endl;
        }
    }
}