题解 | #单链表的排序#

#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 the head node
# @return ListNode类
#
class Solution:
    def sortInList(self , head: ListNode) -> ListNode:
        # write code here
        list0 = []
        while(head):
            list0.append(head.val)
            head = head.next
        list0.sort()
        temp = ListNode(0)
        pre = temp
        for x in list0:
            temp.next = ListNode(x)
            temp = temp.next
        return pre.next