题解 | #简单密码#

对于字母和数字的对应：可以直接用 in 进行判断，然后进行转换； 对于大写字母转化：可以利用内置函数 ord() 和 chr() 进行，如果是 'Z' 则单独转化为 'a' 其他情况不变，于是 Python 代码如下

def password(s):
    a = ''
    for item in s:
        if item in ['a','b','c']:
            item = '2'
        elif item in ['d','e','f']:
            item = '3'
        elif item in ['g','h','i']:
            item = '4'
        elif item in ['j','k','l']:
            item = '5'
        elif item in ['m','n','o']:
            item = '6'
        elif item in ['p','q','r','s']:
            item = '7'
        elif item in ['t','u','v']:
            item = '8'
        elif item in ['w','x','y','z']:
            item = '9'
        elif ord('A') <= ord(item) <= ord('Z'):
            item = chr(ord(item.lower()) + 1) if item != 'Z' else 'a'
        else:
            item = item
        a = a + item
    print(a)
password(input())