题解 | #反转链表#
反转链表
http://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
class ListNode:
def init(self, x):
self.val = x
self.next = None
代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
@param head ListNode类
@return ListNode类
class Solution: def ReverseList(self , head: ListNode) -> ListNode: if not head: return head pre=None while head is not None: temp=head.next head.next=pre pre=head head=temp return pre
查看11道真题和解析