题解 | #字符串旋转#
字符串编码
http://www.nowcoder.com/practice/56a487c342a64d2ea4c3a0b0144b42d0
s=input().strip()
p=''
c=1
for i in range(len(s)):
if len(s)>=2:
if i+1<len(s) and s[i]==s[i+1]:
c+=1
else:
p+=str(c)
p+=s[i]
c=1
else:
p+=str(c)
p+=s
print(p)
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