题解 | #字符串排序#
字符串排序
http://www.nowcoder.com/practice/5190a1db6f4f4ddb92fd9c365c944584
while True:
try:
a = list(input())
lst = [i for i in a if i.isalpha()]
lst.sort(key=str.upper)
count = 0
for i,v in enumerate(a):
if v.isalpha():
a[i] = lst[count]
count +=1
print(''.join(a))
except:
break
