题解 | #字符串排序#
字符串排序
http://www.nowcoder.com/practice/5190a1db6f4f4ddb92fd9c365c944584
while True: try: a = list(input()) lst = [i for i in a if i.isalpha()] lst.sort(key=str.upper) count = 0 for i,v in enumerate(a): if v.isalpha(): a[i] = lst[count] count +=1 print(''.join(a)) except: break