题解 | #查找当前薪水详情以及部门编号dept_no#

考点：group by/join

• max:为了print out 1 record
• is not null：为了exclude null values that came out from "left join"

select sa.emp_no, max(sa.salary), sa.from_date, sa.to_date, dept.dept_no
from salaries sa
left join dept_manager dept
on sa.emp_no = dept.emp_no
where dept.dept_no is not NULL
group by dept.dept_no
order by sa.emp_no , sa.salary asc