题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
@param number int整型
@return int整型
class Solution: def jumpFloor(self,number): list1=[0,1,2] if number==1 or number==2: return number for i in range(number-1)[1:]: list1.append(list1[i]+list1[i+1]) return list1[-1]
