题解 | #n的阶乘#
n的阶乘
http://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include<iostream>
using namespace std;
int main(){
long long int f[21];
int n;
cin>>n;
f[0]=1;
f[1]=1;
for(int i=1;i<=n;++i){
f[i] = f[i-1]*i;
}
cout<<f[n];
return 0;
}
