题解 | #公共子串计算#
公共子串计算
http://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
def myfunc(x, y):
for i in range(len(x),0,-1):
for j in range(len(x)-i+1):
if x[j:j+i] in y:
return i
return 0
while True:
try:
a,b = input().lower(), input().lower()
if len(a) > len(b):
a,b = b,a
print(myfunc(a, b))
except:
break
