题解 | #2的n次方计算#
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include<iostream>
using namespace std;
int main()
{
int n;
cin >> n;
cout << (1<<n) << endl;
return 0;
}
(1<<n)就是2的n次方
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include<iostream>
using namespace std;
int main()
{
int n;
cin >> n;
cout << (1<<n) << endl;
return 0;
}
(1<<n)就是2的n次方
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