题解 | #计算日期到天数转换#

#include <iostream>
using namespace std;
int main()
{
    int year,mon,day;
    int data[]={31,28,31,30,31,30,31,31,30,31,30,31};
    while(cin>>year>>mon>>day)
    {
        int sum;
        for(int i=0;i<mon-1;i++)
        {
              sum=sum+data[i];
        }
        if((year%400==0||(year%4==0&&year%100!=0))&&mon>2)
            sum=sum+1+day;
        else 
            sum=sum+day;
        cout<<sum<<endl;

    }
    return 0;
}