题解 | #提取不重复的整数#
提取不重复的整数
http://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
求模和求余
num1 = int(input())
test = []
while True:
flag = 0
k = num1 % 10
for i in test:
if k == i:
flag = 1
if flag == 0:
test.append(k)
num1 = num1 // 10
if num1 == 0:
break
ans = 0
l = len(test)
for i in range(l):
ans += test[i]*(10**(l-i-1))
print(ans)
