题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
input()
except EOFError:
break
li = input().split()
i = int(input())
print(li[-i] if i else 0)