题解 | #字符串反转#
字符串反转
http://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
include <stdio.h>
include <string.h>
int main(void)
{
char source[1000];
scanf("%s", source);
int len = strlen(source);
char *p = source + len - 1;
int i;
for (i = 0; i < len; i++)
{
printf("%c", *p--);
}
return 0;
}
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