题解 | #二叉树的镜像#
二叉树的镜像
http://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
struct TreeNode* Mirror(struct TreeNode* pRoot ) {
// write code here
if(pRoot == NULL)
return pRoot;
struct TreeNode* tmp = NULL;
tmp = pRoot->left;
pRoot->left = pRoot->right;
pRoot->right = tmp;
Mirror(pRoot->left);
Mirror(pRoot->right);
return pRoot;
}
查看27道真题和解析
