题解 | #字符统计#
字符统计
http://www.nowcoder.com/practice/c1f9561de1e240099bdb904765da9ad0
#先用字典统计字符的个数
#再创建字符数组
#按照次数降序排序.
#减去该字母的ASCII码,实现次数相同,按ASCII码的升序输出
while True:
try:
s = input()
dic = {}
for c in s:
if c not in dic:
dic[c] = s.count(c)
c_l = list(dic.keys())
c_l.sort(key = lambda x:dic[x] * 1000 - ord(x), reverse = True)
print("".join(c_l))
except:
break
投递联发科技等公司10个岗位