C++递归解法
二叉树的镜像
http://www.nowcoder.com/questionTerminal/a9d0ecbacef9410ca97463e4a5c83be7
C++递归:
//递归终止条件,左右节点都为空
TreeNode* Mirror(TreeNode* pRoot) {
if(pRoot == NULL)
return pRoot;
if(!pRoot->left && !pRoot->right) //递归终止条件
return pRoot;
SwapNode(pRoot);
Mirror(pRoot->left);
Mirror(pRoot->right);
return pRoot; //返回根节点
}//交换当前节点左右
void SwapNode(TreeNode *pRoot)
{
TreeNode *pTmp = NULL;
pTmp = pRoot->left;
pRoot->left = pRoot->right;
pRoot->right = pTmp;
}

