PAT基础编程题目-7-20 打印九九口诀表

题目详情

题目详情：https://pintia.cn/problem-sets/14/problems/800

解答

C语言版

#include<stdio.h>
int main() {
   
	int N;
	scanf("%d", &N);
	for (int i = 1; i <= N; i++) {
   
		for (int j = 1; j <= i; j++) {
   
			printf("%d*%d=%-4d", j, i, i * j);
		}
		if (i<N)
			printf("\n");
	}
	return 0;
}

C++版

#include<iostream>
#include<iomanip>
using namespace std;
int main() {
   
	int N;
	cin >> N;
	for (int i = 1; i <= N; i++) {
   
		for (int j = 1; j <= i; j++) {
   
			cout << j << "*" << i << "=" << setw(4) << setiosflags(ios::left) << i * j;
		}
		if (i < N)
			cout << endl;
	}
	return 0;
}

Java版

import java.util.Scanner;
public class Main{
   

	public static void main(String[] args) {
   
		int N = 0;
		Scanner scanner = new Scanner(System.in);
		if (scanner.hasNext()) {
   
			N = scanner.nextInt();
		}
		scanner.close();
		for (int i = 1; i <= N; i++) {
   
			for (int j = 1; j <= i; j++) {
   
				System.out.print(j+"*"+i+"="+String.format("%1$-4d", i*j));
			}
			if (i < N)
				System.out.println();
		}

	}

}

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