找“异数“

思路就是全部化为十进制，只出现一次的数字用输入的形式记录，再出现就用0覆盖记录

import collections
nums=collections.OrderedDict()
while True:
    try:
        s=input()
        n,m=s.split('#')
    except:
        break
    num=int(m,int(n))
    if num not in nums:
        nums[num]=s
    else:
        nums[num]=0
have = False
for i in nums:
    if nums[i]:
        print(nums[i])
        have = True
if not have:
    print('None')