HDU 1113 Word Amalgamation

Problem Description
In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four words. Your task is to write a program that can unscramble words.
 

Input
The input contains four parts:

1. a dictionary, which consists of at least one and at most 100 words, one per line;
2. a line containing XXXXXX, which signals the end of the dictionary;
3. one or more scrambled `words' that you must unscramble, each on a line by itself; and
4. another line containing XXXXXX, which signals the end of the file.

All words, including both dictionary words and scrambled words, consist only of lowercase English letters and will be at least one and at most six characters long. (Note that the sentinel XXXXXX contains uppercase X's.) The dictionary is not necessarily in sorted order, but each word in the dictionary is unique.
 

Output
For each scrambled word in the input, output an alphabetical list of all dictionary words that can be formed by rearranging the letters in the scrambled word. Each word in this list must appear on a line by itself. If the list is empty (because no dictionary words can be formed), output the line ``NOT A VALID WORD" instead. In either case, output a line containing six asterisks to signal the end of the list.
 

Sample Input
tarp given score refund only trap work earn course pepper part XXXXXX resco nfudre aptr sett oresuc XXXXXX
 

Sample Output
score ****** refund ****** part tarp trap ****** NOT A VALID WORD ****** course

******

题目大意:

输入包含四个部分: 1。由至少一个和最多100个单词组成的字典,每行一个; 2。一行xxxxxx,字典的结束信号; 3。输入信号文件 4。另一条线包含xxxxxx,信号文件的结束。

找出字典中和信号文件字母一样的按字典序输出,没有时输出“NOT A VALID WORD”,每个输入后跟“******”。

c++

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<algorithm>
using namespace std;
struct zf
{
    string a;
};
bool cmp(zf a,zf b)
{
    return a.a<b.a;
}
int bj(int a[],int b[])
{
    int c;
    for(c=0;c<26;c++)
    {
        if(a[c]!=b[c])
            return 0;
    }
    return 1;
}
int main()
{
    zf a[1000],b[1000];
    int c[30],m[30];
    int d,e,f,g,h,n,l,q,p;
    d=0;e=0;
    while(1)
    {
        cin>>a[d].a;
        if(a[d].a=="XXXXXX")    //跳出字典的输入
            break;
        d++;
    }
    sort(a,a+d,cmp);           //将字典按字典序排列
    while(1)
    {
        cin>>b[e].a;
        if(b[e].a=="XXXXXX")    //跳出查找的输入
            break;
        h=0;
        l=b[e].a.size();
        for(g=0;g<d;g++)
        {
            memset(c,0,sizeof(c));   //用来统计查找的字母个数
            memset(m,0,sizeof(m));   //用来统计字典的字母个数             n=a[g].a.size();
            if(l==n)
            {
                for(q=0;q<l;q++)
                {
                    c[b[e].a[q]-'a']++;
                    m[a[g].a[q]-'a']++;
                }
                p=bj(m,c);
                if(p==1)
                {
                    cout<<a[g].a<<endl;
                    h++;
                }
            }
        }
        if(h==0)
        {
            cout<<"NOT A VALID WORD"<<endl;
        }
        cout<<"******"<<endl;
        e++;
    }
    return 0;
}


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1jian10:48h没写面评会变成这样
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今天周一休息,突发奇想写一篇阶段总结。如题,我已经去了一个和Java彻底毫无关联的行业。曾经我以为自己能在计算机行业发光发热,没想到刚入行一年多就当了逃兵。从最开始的热爱到现在一看到代码就厌恶,不知道自己经历了什么。所以我去干什么了?答案是:在成都当了租房销售。上班那会压力大了就念叨着去干租房中介,但是一直下不去这个决心,想着自己学了四年多的计算机知识,终究还是不甘心。终于在某一天准备八股文的时候,看着无数篇和工作内容关系不大的理论知识,那一刻下定决心,决定尝试一下销售行业,也算是给自己一个交代。后面阴差阳错的投了成都自如去当租房管家,没想到面试很顺利,在当天一百多个面试的人里面,我成为了为数不多通过的几个幸运儿之一。目前已经培训通过,正式入职,也开了单,也有压力但是每天过得很开心,真心喜欢那种和人交流的感觉,哪怕是最后没有选择找我租房。说这些也是想告诉那些大三,大四正在找Java实习而焦虑的同学:你们现在还年轻,选择很多,容错率也很高,可以尽情去尝试自己喜欢的行业和工作。不用因为某一次的面试没通过或者简历石沉大海而焦虑,更不用因为身边人都在挤编程的独木桥就强迫自己跟风。也算是自己的碎碎念吧,也希望自己能在新的领域取得一点小成就。也祝牛油工作顺利!
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