L3-001 凑零钱

动态规划+记录方案

const int maxn = 1e4+10,maxm = 1e2+10;
int dp[maxn][maxm];
int fa[maxm];
int a[maxn];
int main(void)
{
    
    int N,M;cin>>N>>M;
    for(int i = 1;i <= N; ++i) cin>>a[i];
    sort(a+1,a+N+1);
    for(int i = 0;i <= M; ++i)
    	fa[i] = -1;
    fa[0] = 0;
    for(int i = N;i >= 1; --i){
    	for(int j = M;j >= a[i]; --j){
    		if(fa[j-a[i]] != -1)
    			dp[i][j] = fa[j-a[i]],fa[j] = i;
    	}
    }
    // for(int i = 1;i <= M; ++i)
    // cout<<dp[1][i]<<endl;
    if(fa[M] == -1)
    	puts("No Solution");
    else
    {
    	// cout<<fa[M]<<endl;
    	int j = M;
    	bool first = true;
    	for(int now = fa[j];now != 0;){
    		if(first)first = false;
    		else putchar(' ');
    		printf("%d",a[now]);
    		int tmp = j-a[now];
    		now = dp[now][j];
    		j = tmp;
    		// cout<<j<<endl;
    	}
    	// printf("%d",j);

    }
    


   return 0;
}