class Solution: def ReverseList(self , pHead): if pHead == None or pHead.next == None: #若头节点为空则返回 return pHead leftpoint = pHead #定义三个空节点,left指向头节点 midpoint = leftpoint.next #mid指向头节点的下一个节点 rightpoint = midpoint.next #right指向mid的下一个节点 leftpoint.next = None #将头节点指向空节点 while rightpoint != None: midpoi...