思路参考:C++代码实现 #include<iostream> using namespace std; int main() { long n,l; cin >> n >> l; double a = 0; long i = l; for(; i<=100; i++) { double b = (double)(2*n - i*(i-1)) / (2 * i); if(b - long(b) == 0) { a = b; bre...