#include<bits/stdc++.h>using namespace std;const int N = 1e5 + 10;using ll = long long;int n;ll a[N] = {0};ll mex,ans = 0;bool correct(ll *a) //检测是否满足题意，即每个数都相同，不满足为false 满足为true{ for(int i = 0;i < n;i++) { if(i+1 < n && a[i+1] != a[i]) return false; } return true;}int main(){ ci...
