sql入门级,还请大佬们看看我的这个性能怎么样 select qd.difficult_level,sum(if(qpd.result='right',1,0))/count(qpd.result) as rate from user_profile up,question_practice_detail qpd,question_detail qd where up.university='浙江大学' and up.device_id=qpd.device_id and qpd.question_id =qd.question_id group by qd.difficult_level o...