E.Sum of gcd of Tuples (Hard) 定义: f(d)f(d)f(d)为gcd(A1,A2,A3,..,An)=dgcd(A_1,A_2,A_3,..,A_n)=dgcd(A1,A2,A3,..,An)=d的方案数 F(d)F(d)F(d)为gcd(A1,A2,A3,..,An)gcd(A_1,A_2,A_3,..,A_n)gcd(A1,A2,A3,..,An)为ddd的倍数的方案数 显然有, F(d)=∑d∣d′f(d′),d′为d的倍数,下面不再解释F(d)=\sum_{d|d'}f(d'),d'为d的倍数,下面不再解释F(d)=d∣d′∑f(d′)...