nums[1,2,3,4,5] 2 mid = 0 + (5-1)/2 = 2 nums[2] > 2 -> 找nums[1,2] public int search (int[] nums, int target) { int index = binarySearch(nums, target, 0, nums.length-1); for(int i = index; i >= 0 && nums[i] == nums[index]; i--){ index = i; } return index; } public int binarySearch(in...
