select 入职工资.emp_no , 最终工资.salary - 入职工资.salary growth #表头# from (select emp_no, salary from (select emp_no, salary , rank()over(partition by emp_no order by from_date) rk1 from salaries ) ranking1 where ranking1.rk1 = 1 ) 入职工资 #按from_date正序编号可以获得入职工资# right join (select emp_no, salary from (select e...