SELECT tag,difficulty,ROUND((SUM(score)-max(score)-MIN(score))/(COUNT(score)-2),1) AS clip_avg_socre FROM exam_record as er join examination_info AS ei WHERE er.exam_id=ei.exam_id and difficulty='hard' and tag='SQL' select tag,difficulty,round((sum(score) - max(score)-min(score)) / (count(score)-2),...